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The value of $\sin ^{-1}(\sin 10)$ is
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$3 \pi-10$
$\begin{aligned} & \text{Since } 3 \pi \lt 10 \lt 3 \pi+\frac{\pi}{2} \Rightarrow 0 \lt 10-3 \pi \lt \frac{\pi}{2} \\ \Rightarrow & \frac{-\pi}{2} \lt 3 \pi-10 \lt 0 \Rightarrow \sin ^{-1}\{\sin (3 \pi-10)\}=3 \pi-10\end{aligned}$
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