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Question: Answered & Verified by Expert
The value of the definite integral I=ln32ln23ln2-tan7x2+tan7xdx is equal to
MathematicsDefinite IntegrationJEE Main
Options:
  • A ln4
  • B ln2
  • C 0
  • D ln12
Solution:
1133 Upvotes Verified Answer
The correct answer is: 0

If fx=ln2-tan7x2+tan7x, then 
f-x=ln2+tan7x2-tan7x
=-ln2-tan7x2+tan7x
=-fx

So, fx is an odd function
Hence, ln32ln23fxdx=0

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