The value of the integral ∫ 0 4 x 3 - 6 x 2 + 12 x - 4 + x - 2 cos ⁡ x - 2 d x is equal to

Question

The value of the integral ∫ 0 4 x 3 - 6 x 2 + 12 x - 4 + x - 2 cos ⁡ x - 2 d x is equal to, 12, 16, 0, 10

MARKS App · Accepted Answer

Let, I = ∫ 0 4 x - 2 3 + x - 2 cos ⁡ x - 2 + 4 d x Let x - 2 = t ⇒ d x = d t ⇒ I = ∫ - 2 2 t 3 + t cos ⁡ t + 4 d t (As t 3 + t cos ⁡ t is an odd function) ⇒ I = 2 ∫ 0 2 4 d t = 16

Search any question & find its solution

Looking for more such questions to practice?