The value of the integral I = ∫ 1 2 t t + t 1 + ln t d t is equal to ( . and . denotes the greatest integer and fractional part function respectively)

Question

The value of the integral I = ∫ 1 2 t t + t 1 + ln t d t is equal to ( . and . denotes the greatest integer and fractional part function respectively), 0, 1, 2, 3

MARKS App · Accepted Answer

As t = 0 , we get, I = ∫ 1 2 t t 1 + ln ⁡ t d t = ∫ 1 2 d t t = t t 1 2 = 2 2 – 1 1 = 3

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