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The value of the ‘spin only’ magnetic moment for one of the following configurations is 2.84 BM. the correct one
Options:
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1911 Upvotes
Verified Answer
The correct answer is:
$d^4$ (in strong ligand field)
As we know,
Magnetic moment \(=\sqrt{n(n+2)}=2.84\)
so \(n=2\)
\(d^4\) (in strong ligand field) has two unpaired electron in octahedral field.
Hence, option (a) is correct.
All others doesnt have two unpaired electrons.
Magnetic moment \(=\sqrt{n(n+2)}=2.84\)
so \(n=2\)
\(d^4\) (in strong ligand field) has two unpaired electron in octahedral field.
Hence, option (a) is correct.
All others doesnt have two unpaired electrons.
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