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The variance of first 20 natural numbers is
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The correct answer is:
$133 / 4$
Variance of $n$ natural numbers $=\frac{n^{2}-1}{12}=\frac{(20)^{2}-1}{12} \quad$ $[\because n=20]$,
$=\frac{400-1}{12}=\frac{399}{12}=\frac{133}{4}$
$=\frac{400-1}{12}=\frac{399}{12}=\frac{133}{4}$
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