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The velocity and acceleration vectors of a particle undergoing circular motion are $\overrightarrow{\mathrm{v}}=2 \hat{\mathrm{i}} \mathrm{m} / \mathrm{s}$ and $\overrightarrow{\mathrm{a}}=2 \hat{\mathrm{i}}+4 \hat{\mathrm{j}} \mathrm{m} / \mathrm{s}^{2}$ respectively at an instant of time. The radius of the circle is -
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The correct answer is:
$1 \mathrm{~m}$
It can be observed that component of acceleration perpendicular to velocity is $\mathrm{a}=4 \mathrm{~m} / \mathrm{s}^{2}$
$$
\therefore \text { radius }=\frac{\mathrm{v}^{2}}{\mathrm{a}_{\mathrm{c}}}=\frac{(2)^{2}}{4}=1 \text { metre }
$$
$$
\therefore \text { radius }=\frac{\mathrm{v}^{2}}{\mathrm{a}_{\mathrm{c}}}=\frac{(2)^{2}}{4}=1 \text { metre }
$$
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