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Question: Answered & Verified by Expert
Three particles of masses 50 g, 100 g and 150 g are placed at the vertices of an equilateral triangle of side 1 m (as shown in the figure). The x,y coordinates of the centre of mass will be:

PhysicsCenter of Mass Momentum and CollisionJEE MainJEE Main 2019 (12 Apr Shift 2)
Options:
  • A 712 m,34 m
  • B 712 m,38 m
  • C 34 m,512 m
  • D 38 m,712 m
Solution:
2463 Upvotes Verified Answer
The correct answer is: 712 m,34 m
Coordinates of A :0, 0
B:12 m,  32 m
C :(1 m, 0)
Coordinates of center of mass
xcm,ycm=50×0+150×12+100×150+150+100 m, 50×0+150×32+100×050+150+100 m
=712 m, 34 m

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