To prepare XeF 6 ⋅ Xe and F 2 are mixed at 573 K and 60 − 70 bar in the ratio of

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To prepare $\mathrm{XeF}_6 \cdot \mathrm{Xe}$ and $\mathrm{F}_2$ are mixed at $573 \mathrm{~K}$ and $60-70$ bar in the ratio of

Chemistryp Block Elements (Group 15, 16, 17 & 18)AP EAMCETAP EAMCET 2017 (26 Apr Shift 1)

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Solution:

1494 Upvotes Verified Answer

The correct answer is: 1: 20

$\underset{(1: 20)}{\mathrm{Xe}+\mathrm{F}_2} \frac{573 \mathrm{~K}}{60-70 \mathrm{bar}} \mathrm{XeF}_6$

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