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To remove the second term of the equation $x^4-8 x^3+x^2-x+3=0$, diminish the roots of the equation by
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The correct answer is:
$2$
We have, $x^4-8 x^3+x^2-x+3=0$
$$
h=-\frac{\text { coefficient of } x^3}{\text { number of roots }}=\frac{-(-8)}{4}=2
$$
$$
h=-\frac{\text { coefficient of } x^3}{\text { number of roots }}=\frac{-(-8)}{4}=2
$$
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