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Question: Answered & Verified by Expert
Two balls A and B are projected from the same position with horizontal velocity 20 m s-1 and 5 m s-1 as shown. The separation between these two bodies at the moment their velocities become perpendicular to each other is x m. The value of x is

PhysicsMotion In Two DimensionsJEE Main
Solution:
1360 Upvotes Verified Answer
The correct answer is: 25

v1=5i^-gtj^ u1=5

v2=20i^-gtj^ u2=20

As v1 and v2 are perpendicular, 

v1·v2=0
t=u1u2g
srel=urel×t
= (u1+u2) t
=u1+u2u1u2g
=25×1010=25 m

 

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