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Question: Answered & Verified by Expert
Two blocks $A$ and $B$ each of $20 \mathrm{~kg}$ lying on a frictionless table are connected by a light string. The system is pulled horizontally with an acceleration of $2 \mathrm{~ms}^{-2}$ by a force $F$ on $B$. The tension in the string will be
PhysicsLaws of MotionMHT CETMHT CET 2012
Options:
  • A $10 \mathrm{~N}$
  • B $40 \mathrm{~N}$
  • C $100 \mathrm{~N}$
  • D $120 \mathrm{~N}$
Solution:
2510 Upvotes Verified Answer
The correct answer is: $40 \mathrm{~N}$
The given situation can be shown as


$\text { The tension } T=M_{A} \times a$
here,
$\begin{aligned}
M_{A} &=20 \mathrm{~kg} \text { and } a=2 \mathrm{~ms}^{-2} \\
T &=20 \times 2=40 \mathrm{~N}
\end{aligned}$

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