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Two blocks of $2 \mathrm{~kg}$ and $1 \mathrm{~kg}$ are in contact on a frictionless table. If a force of $3 \mathrm{~N}$ is applied on $2 \mathrm{~kg}$ block, then the force of contact between the two blocks will be :
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Verified Answer
The correct answer is:
$1 \mathrm{~N}$
Hints: Common acceleration $=\frac{3}{3}=1 \mathrm{~m} / \mathrm{sec}^2$
$$
\mathrm{N}_1=1 \mathrm{~N}
$$
$$
\mathrm{N}_1=1 \mathrm{~N}
$$
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