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Question: Answered & Verified by Expert
Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of 14 m s-1 to the heavier block in the direction of the lighter block. The velocity of the centre of mass in m s-1 is 2n, then n=
PhysicsCenter of Mass Momentum and CollisionJEE Main
Solution:
2858 Upvotes Verified Answer
The correct answer is: 5
vCM=m1v1+m2v2m1+m2

10×14+4×010+4=10×1414=10 m s-1 =2nn=5

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