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Two bodies of unequal mass are moving in the same direction with equal kinetic energy. The two bodies are brought to rest by applying retarding force of same magnitude. How would the distance moved by them before coming to rest compare?
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By work energy theorem change in K.E. is equal to work done by body.
i.e., change in K.E. = Work done by the retarding force.
K.E. of the body $=$ Retarding force $\times$ Displacement
As K.E. of the bodies and retarding forces applied on them are same. Hence, both bodies will travel equal displacement or distances before coming to rest.
i.e., change in K.E. = Work done by the retarding force.
K.E. of the body $=$ Retarding force $\times$ Displacement
As K.E. of the bodies and retarding forces applied on them are same. Hence, both bodies will travel equal displacement or distances before coming to rest.
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