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Two coherent plane light waves of equal amplitude makes a small angle $\alpha(< < 1)$ with each other. They fall almost normally on a screen. If $\lambda$ is the wavelength of light waves, the fringe width $\Delta x$ of interference patterns of the two sets of waves on the screen is
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The correct answer is:
$\frac{\lambda}{(2 \alpha)}$
$\frac{\lambda}{(2 \alpha)}$
$\Delta x=\frac{\lambda}{(2 \alpha)}$
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