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Two dice are rolled. If a random variable $X$ denotes the sum of the numbers on them and $\mu$ denotes the mean of $X$, then $\mu+P(X < 5)+P(X>9)+P(x=7)=$
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Verified Answer
The correct answer is:
$\frac{15}{2}$
$X=$ denotes the sum of number when two dice are rolled
$$
\mu(\text { Mean })=\Sigma P_i X_i=\frac{252}{36}=7
$$
Now, $\mu-p(X < 5)+P(X>9)+p(X=7)$
$$
\frac{252}{36}+\frac{6}{36}+\frac{6}{36}+\frac{6}{36}=\frac{270}{36}=\frac{15}{2}
$$
$$
\mu(\text { Mean })=\Sigma P_i X_i=\frac{252}{36}=7
$$
Now, $\mu-p(X < 5)+P(X>9)+p(X=7)$
$$
\frac{252}{36}+\frac{6}{36}+\frac{6}{36}+\frac{6}{36}=\frac{270}{36}=\frac{15}{2}
$$
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