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Two flasks $X$ and $Y$ have capacity $1 \mathrm{~L}$ and $2 \mathrm{~L}$ respectively and each of them contains 1 mole of a gas. The temperatures of the flasks are so adjusted that average speed of molecules in $X$ is twice as those in $Y$. The pressure in flask $X$ would be
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The correct answer is:
8 times of that in $Y$.
$P=\frac{1}{3} \frac{m n u^2}{V}$
$$
\frac{P_X}{P_Y}=\frac{n_X u_X V_Y}{n_Y u_Y V_x}=\frac{\left(N_0 / 1000\right)}{\left(N_0 / 2000\right)} \times 2 \times \frac{2}{1}=8
$$
$$
\frac{P_X}{P_Y}=\frac{n_X u_X V_Y}{n_Y u_Y V_x}=\frac{\left(N_0 / 1000\right)}{\left(N_0 / 2000\right)} \times 2 \times \frac{2}{1}=8
$$
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