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Two identical cells each of emf $\mathrm{E}$ and internal resistance $\mathrm{r}$ are connected in parallel with an external resistance $\mathrm{R}$. To get maximum power developed across $R$, the value of $R$ is
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The correct answer is:
$R=r / 2$
$R_{e q}=\frac{r}{2}$
$I=\frac{2 E}{r+2 R}$
For max. power consumption. I should be max. So denominator should be min. for that
$r+2 R=(\sqrt{r}, \quad)$
$I=\frac{2 E}{r+2 R}$
For max. power consumption. I should be max. So denominator should be min. for that
$r+2 R=(\sqrt{r}, \quad)$
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