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Two oxides of nitrogen, $\mathrm{NO}$ and $\mathrm{NO}_2$ react together at $253 \mathrm{~K}$ and form a compound of nitrogen $X$. $X$ reacts with water to yield another compound of nitrogen $Y$. The shape of the anion of $Y$ molecule is :
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The correct answer is:
triangular planar
$\mathrm{NO}+\mathrm{NO}_2 \stackrel{253^{\circ} \mathrm{C}}{\longrightarrow} \mathrm{N}_2 \mathrm{O}_3$
$\underset{\text { (X) }}{\mathrm{N}_2 \mathrm{O}_3+\mathrm{H}_2 \mathrm{O} }\longrightarrow \underset{\text { (Y) }}{2 \mathrm{HNO}_2}$
$\therefore$ Anion of $\gamma$ is $\mathrm{NO}_2^{-}$
It's shape is triangular planar.
$\underset{\text { (X) }}{\mathrm{N}_2 \mathrm{O}_3+\mathrm{H}_2 \mathrm{O} }\longrightarrow \underset{\text { (Y) }}{2 \mathrm{HNO}_2}$
$\therefore$ Anion of $\gamma$ is $\mathrm{NO}_2^{-}$
It's shape is triangular planar.
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