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"Two particles $A$ and $B$ are moving as shown. in the figure.
Their total angular momentum about the point $O$ is
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Their total angular momentum about the point $O$ is
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Verified Answer
The correct answer is:
$9.8 \mathrm{kg} \mathrm{m}^{2} / \mathrm{s}$
Total angular momentum about $O$ is given as,
$$
\begin{aligned}
\mathbf{L} &=\mathbf{L}_{1}+\mathbf{L}_{2}=m_{1} V_{1} I_{1}+m_{2} V_{2} I_{2} \\
&=-6.5 \times 2.2 \times 1.5+3.1 \times 3.6 \times 2.8 \\
&=-21.45+31.248=9.8 \mathrm{kgm}^{2} / \mathrm{s}
\end{aligned}
$$
$$
\begin{aligned}
\mathbf{L} &=\mathbf{L}_{1}+\mathbf{L}_{2}=m_{1} V_{1} I_{1}+m_{2} V_{2} I_{2} \\
&=-6.5 \times 2.2 \times 1.5+3.1 \times 3.6 \times 2.8 \\
&=-21.45+31.248=9.8 \mathrm{kgm}^{2} / \mathrm{s}
\end{aligned}
$$
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