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Question: Answered & Verified by Expert
Two particles of mass 1 kg and 3 kg move towards each other under their mutual force of attraction. No other force acts on them. When the relative velocity of approach of two particles is 2 m s-1, their centre of mass has a velocity of 0.5 m s-1. When the relative velocity of approach becomes 3 m s-1, the velocity of the centre of mass will be
PhysicsCenter of Mass Momentum and CollisionNEET
Options:
  • A 0.75 m s-1
     
  • B 0.5 m s-1
     
  • C 10 m s-1
     
  • D 1.25 m s-1
     
Solution:
2437 Upvotes Verified Answer
The correct answer is: 0.5 m s-1
 
Net external force on the system is zero. So, the velocity of the centre of mass will remain constant, i.e., 0.5 m s-1.

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