Two point masses connected by an ideal string are placed on a smooth horizontal surface as shown in the diagram. A sharp impulse of 10 k g - m s - 1 is given to the 5 k g mass. The velocity of the 10 k g mass will be

Question

Two point masses connected by an ideal string are placed on a smooth horizontal surface as shown in the diagram. A sharp impulse of 10 k g - m s - 1 is given to the 5 k g mass. The velocity of the 10 k g mass will be, 2 3 m s - 1, 1 3 m s - 1, 2 m s - 1, zero

MARKS App · Accepted Answer

Apply impulse equation, along string Impulse = Δ p 10 × 1 2 = 10 + 5 v v = 1 3 m s - 1

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