Two resistors of resistances $ R_{1}=(300 \pm 3) \Omega $ and $ R_{2}=(500 \pm 4) \Omega $ are connected in series. The equivalent resistance of the series combination is

Question

Two resistors of resistances $ R_{1}=(300 \pm 3) \Omega $ and $ R_{2}=(500 \pm 4) \Omega $ are connected in series. The equivalent resistance of the series combination is, $ (800 \pm 1) \Omega $, $ (800 \pm 7) \Omega $, $ (200 \pm 7) \Omega $, $ (200 \pm 1) \Omega $

MARKS App · Accepted Answer

The equivalent resistance of series combination is R s = R 1 + R 2 = 300 Ω + 500 Ω = 800 Ω The error in equivalent resistance is given by ∆ R = ± ∆ R 1 + ∆ R 2 = ± 3 + 4 Ω = ± 7 Ω Hence, the equivalent resistance along with error is ( 800 ± 7 ) Ω

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