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Two tangents \(P Q\) and \(P R\) drawn to the circle \(x^2+y^2-2 x-4 y-20=0\) from point \(P(16,7)\). Ifthe centre of the circle is \(C\) then the area of quadrilateral \(\mathrm{PQCR}\) is
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75 sq. unit
Area \(\mathrm{PQCR}=2~ \triangle ~\mathrm{PQC}=2 \times \frac{1}{2} \mathrm{~L} \times r\)
where \(\mathrm{L}=\) length of tangent and \(r=\) radius of circle.
\(\mathrm{L}=\sqrt{\mathrm{S}_1}=15 \text { and } \mathrm{r}=\sqrt{1+4+20}=5\)
Hence the required area \(=75\) sq. units.
where \(\mathrm{L}=\) length of tangent and \(r=\) radius of circle.
\(\mathrm{L}=\sqrt{\mathrm{S}_1}=15 \text { and } \mathrm{r}=\sqrt{1+4+20}=5\)
Hence the required area \(=75\) sq. units.
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