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Two trains, each $30 \mathrm{~m}$ long are travelling in opposite directions with velocities $5 \mathrm{~m} / \mathrm{s}$ and $10 \mathrm{~m} / \mathrm{s}$. They will cross after
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$4 \mathrm{~s}$
Relative velocity of one train w. r. t other $=5+0$
$=15 \mathrm{~m} / \mathrm{s}$
Total length to cross $(\mathrm{L})=30+30=60 \mathrm{~m}$
$\therefore \quad t=\frac{L}{V}=\frac{60}{15}=4 s$
$=15 \mathrm{~m} / \mathrm{s}$
Total length to cross $(\mathrm{L})=30+30=60 \mathrm{~m}$
$\therefore \quad t=\frac{L}{V}=\frac{60}{15}=4 s$
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