Search any question & find its solution
Question:
Answered & Verified by Expert
Two tuning forks of frequencies $320 \mathrm{~Hz}$ and $480 \mathrm{~Hz}$ are sounded together to produce sound waves. They velocity of sound in air is $320 \mathrm{~ms}^{-1}$. The difference between wavelengths of these waves is nearly
Options:
Solution:
2100 Upvotes
Verified Answer
The correct answer is:
33 cm
$\begin{aligned} & \lambda_1-\lambda_2=\frac{\mathrm{V}}{\mathrm{f}_1}-\frac{\mathrm{V}}{\mathrm{f}_2} \\ & =\frac{320}{320}-\frac{320}{480} \\ & =1-\frac{2}{3}=\frac{1}{3} \mathrm{~m}=0.33 \mathrm{~m}=33 \mathrm{~cm}\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.