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Two wires of same diameter of the same material having the length $l$ and $2 l$. If the force $\mathrm{F}$ is applied on each, the ratio of the work done in the two wires will be
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$1: 2$
$W=\frac{1}{2} F l \quad \therefore W \propto l$ ( $F$ is constant)
$\therefore \frac{W_1}{W_2}=\frac{l_1}{l_2}=\frac{l}{2 l}=\frac{1}{2}$
$\therefore \frac{W_1}{W_2}=\frac{l_1}{l_2}=\frac{l}{2 l}=\frac{1}{2}$
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