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Volume of a balloon at $25^{\circ} \mathrm{C}$ and 1 bar pressure is $2 \cdot 27 \mathrm{~L}$. If the pressure of the gas in balloon is reduced to $0.227$ bar, what is the rise in volume of a gas?
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$\quad 7 \cdot 73 \mathrm{~L}$
$P_{1}=1 \mathrm{~bar}, \quad V_{1}=2.27 \mathrm{~L}$
$\mathrm{P}_{2}=0.227 \mathrm{~bar}, \quad \mathrm{V}_{2}=?$
According to Boyle's Law, $P_{1} V_{1}=P_{2} V_{2}$
$\therefore V_{2}=\frac{P_{1} V_{1}}{P_{2}}=\frac{1 \times 2.27}{0.227}=10 \mathrm{~L}$
$\therefore$ The rise in volume of gas $=10-2.27=7.73 \mathrm{~L}$
$\mathrm{P}_{2}=0.227 \mathrm{~bar}, \quad \mathrm{V}_{2}=?$
According to Boyle's Law, $P_{1} V_{1}=P_{2} V_{2}$
$\therefore V_{2}=\frac{P_{1} V_{1}}{P_{2}}=\frac{1 \times 2.27}{0.227}=10 \mathrm{~L}$
$\therefore$ The rise in volume of gas $=10-2.27=7.73 \mathrm{~L}$
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