What is the mass of 33.6 dm 3 of methane gas at S.T.P.?, 4.8 × 1 0 − 2 kg, 3.3 × 1 0 − 2 kg, 1.6 × 1 0 − 2 kg, 2.4 × 1 0 − 2 kg

moles of gas = 22.4 volume = 22.4 33.6 = 1.5 mass of ( CH 4 ) methane gas = moles × molar mass = 1.5 × 16 = 24 g = 2.4 × 1 0 − 2 kg

What is the mass of 33.6 dm 3 of methane gas at S.T.P.?

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What is the mass of $33.6 \mathrm{dm}^3$ of methane gas at S.T.P.?

ChemistrySome Basic Concepts of ChemistryMHT CETMHT CET 2021 (23 Sep Shift 2)

Options:

A $4.8 \times 10^{-2} \mathrm{~kg}$
B $3.3 \times 10^{-2} \mathrm{~kg}$
C $1.6 \times 10^{-2} \mathrm{~kg}$
D $2.4 \times 10^{-2} \mathrm{~kg}$

Solution:

1726 Upvotes Verified Answer

The correct answer is: $2.4 \times 10^{-2} \mathrm{~kg}$

$\begin{aligned} & \text { moles of gas }=\frac{\text { volume }}{22.4}=\frac{33.6}{22.4}=1.5 \\ & \text { mass of } \begin{aligned}\left(\mathrm{CH}_4\right) \text { methane gas } & =\text { moles } \times \text { molar mass } \\ & =1.5 \times 16 \\ & =24 \mathrm{~g} \\ & =2.4 \times 10^{-2} \mathrm{~kg}\end{aligned}\end{aligned}$

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