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Which of the following undergoes reduction with hydrogen peroxide in alkaline medium?
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The correct answer is:
$\mathrm{I}_2$
It reduces iodine to iodide ion in alkaline medium.
$\begin{array}{r}\mathrm{I}_2(\mathrm{~s})+\mathrm{H}_2 \mathrm{O}_2(a q)+2 \mathrm{OH}^{-} \longrightarrow \\ 2 \mathrm{I}^{-}(a q)+2 \mathrm{H}_2 \mathrm{O}(\mathrm{l})+\mathrm{O}_2(\mathrm{~g})\end{array}$
$\begin{array}{r}\mathrm{I}_2(\mathrm{~s})+\mathrm{H}_2 \mathrm{O}_2(a q)+2 \mathrm{OH}^{-} \longrightarrow \\ 2 \mathrm{I}^{-}(a q)+2 \mathrm{H}_2 \mathrm{O}(\mathrm{l})+\mathrm{O}_2(\mathrm{~g})\end{array}$
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