For the ideal solution

$\Delta {\text{H}}_{\text{mixture}}=0,$ because new bond formed and break so no enthalpy gain or lose.

$\Delta {\text{S}}_{\text{mixture}}>0,$ because randomness increasing on mixing on a solution.

$\Delta {\text{V}}_{\text{mixture}}=0,$ $e^{-}$ because no new bond for or break so, no force of attraction change.

$\Delta \text{P}={\text{P}}_{\text{observed}}-\Delta {\text{P}}_{\text{Raoult}}=0;$ vapour pressure remains the same because of no force of attraction increase or decrease.