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Question: Answered & Verified by Expert
Which one of the following arrangements represents the correct order of electron gain enthalpy (with negative sign) of the given atomic species?
ChemistryClassification of Elements and Periodicity in PropertiesBITSATBITSAT 2014
Options:
  • A $\quad \mathrm{S}<\mathrm{O}<\mathrm{Cl}<\mathrm{F}$
  • B $\quad \mathrm{Cl}<\mathrm{F}<\mathrm{S}<\mathrm{O}$
  • C $\quad \mathrm{F}<\mathrm{Cl}<\mathrm{O}<\mathrm{S}$
  • D $\quad \mathrm{O}<\mathrm{S}<\mathrm{F}<\mathrm{Cl}$
Solution:
2485 Upvotes Verified Answer
The correct answer is: $\quad \mathrm{O}<\mathrm{S}<\mathrm{F}<\mathrm{Cl}$
The amount of energy released when an electron is added to an isolated gaseous atom to produce a monovalent anion is called electron gain enthalpy.

Electron affinity value generally increase on moving from left to right in a period however there are exceptions of this rule in the case of those atoms which have stable configuration. These atoms resist the addition of extra electron, therefore the low value of electron affinity $\underset{-1.48}{\mathrm{O}}<\underset{-2.0}{\mathrm{~S}}<\underset{-3.6}{\mathrm{~F}}<\underset{-3.8}{\mathrm{Cl}}$

On the other hand $\mathrm{Cl}$, because of its comparatively bigger size than $\mathrm{F}$, allow the addition of an extra electron more easily.

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