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Question: Answered & Verified by Expert
Which one of the following is an inner orbital complex as well as diamagnetic in behaviour?
(Atomic number : $\mathrm{Zn}=30, \mathrm{Cr}=24$, $\mathrm{Co}$ $=27, \mathrm{Ni}=28$ )
ChemistryCoordination CompoundsNEETNEET 2005
Options:
  • A $\left[\mathrm{Zn}\left(\mathrm{NH}_3\right)_6\right]^{2+}$
  • B $\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_6\right]^{3+}$
  • C $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$
  • D $\left[\mathrm{Ni}\left(\mathrm{NH}_3\right)_6\right]^{2+}$
Solution:
2623 Upvotes Verified Answer
The correct answer is: $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$


$d^2 s p^3 \rightarrow$ inner octahedral complex $\&$ diamagnetic.
$$
\left[\mathrm{Zn}\left(\mathrm{NH}_3\right)_6\right]^{2+} \longrightarrow s p^2 d^2
$$
hybridization (outer) and diamagnetic.
$\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_6\right]^{3+} \longrightarrow d^2 s p^3$ (inner) and
paramagnetic.
$\left[\mathrm{Ni}\left(\mathrm{NH}_3\right)_6\right]^{3+} \longrightarrow s p^3 p^2$ (outer) and
paramagnetic.
Related Theory
The main difference between inner and outer orbital complexes is that the hybridization of the atomic orbitals of the central metal atom of inner orbital complex involves inner shell $d$ orbitals whereas the hybridization of the atomic orbitals of the central metal atom of outer orbital complex involves outermost shell d orbitals.

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