Search any question & find its solution
Question:
Answered & Verified by Expert
Which one of the following shows highest magnetic moment?
Options:
Solution:
2550 Upvotes
Verified Answer
The correct answer is:
$\mathrm{Fe}^{2+}$
Atomic number of $\mathrm{Fe}(26)=[\mathrm{Ar}] 3 d^{6} 4 s^{2}$
$$
\mathrm{Fe}^{2+}=[\mathrm{Ar}] 3 d^{6} 4 s^{0}
$$
Number of unpaired electrons $=4$
For Co ${ }^{2+}=[\mathrm{Ar}] 3 d^{7}$
Number of unpaired electrons $=3$
It shows highest magnetic moment. As magnetic moment depends on number of unpaired electrons.
For Cr ${ }^{3+}=[\mathrm{Ar}] 3 d^{3}$
$\therefore$ Number of unpaired electrons $=3$
For $\mathrm{Ni}^{+}=[\mathrm{Ar}] 3 d^{8}$
$\therefore$ Number of unpaired electrons $=2$
$$
\mathrm{Fe}^{2+}=[\mathrm{Ar}] 3 d^{6} 4 s^{0}
$$
Number of unpaired electrons $=4$
For Co ${ }^{2+}=[\mathrm{Ar}] 3 d^{7}$
Number of unpaired electrons $=3$
It shows highest magnetic moment. As magnetic moment depends on number of unpaired electrons.
For Cr ${ }^{3+}=[\mathrm{Ar}] 3 d^{3}$
$\therefore$ Number of unpaired electrons $=3$
For $\mathrm{Ni}^{+}=[\mathrm{Ar}] 3 d^{8}$
$\therefore$ Number of unpaired electrons $=2$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.