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Write the truth table for the circuit shown in figure given below. Name the gate that the circuit resembles.
Solution:
1263 Upvotes
Verified Answer
As the given circuit resemble AND gate. The boolean expression of this circuit is, $\mathrm{V}_0=\mathrm{A} . \mathrm{B}$ i.e., $\mathrm{V}_0$ equals A AND B. The truth table of this gate is
$$
\begin{array}{|c|c|c|}
\hline \mathrm{A} & \mathrm{B} & \mathrm{V}_0=\mathrm{AB} \\
\hline 0 & 0 & 0 \\
0 & 1 & 0 \\
1 & 0 & 0 \\
1 & 1 & 1 \\
\hline
\end{array}
$$
$$
\begin{array}{|c|c|c|}
\hline \mathrm{A} & \mathrm{B} & \mathrm{V}_0=\mathrm{AB} \\
\hline 0 & 0 & 0 \\
0 & 1 & 0 \\
1 & 0 & 0 \\
1 & 1 & 1 \\
\hline
\end{array}
$$
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