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$x-2=t^2, y=2 t$ are the parametric equations of the parabola
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The correct answer is:
$y^2=4(x-2)$
Here $\frac{y}{2}=t$ and $x-2=t^2$
$\Rightarrow \quad(x-2)=\left(\frac{y}{2}\right)^2 \Rightarrow y^2=4(x-2)$.
$\Rightarrow \quad(x-2)=\left(\frac{y}{2}\right)^2 \Rightarrow y^2=4(x-2)$.
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