x 3 + y 3 = 3 x y ⇒ d x d y =, y 2 − x y − x 2 , y 2 + x y + x 2 , y 2 + x y − x 2 , y 2 − x y + x 2

x 3 + y 3 = 3 x y ⇒ d x d y =

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$x^3+y^3=3 x y \Rightarrow \frac{d y}{d x}=$

MathematicsDifferentiationAP EAMCETAP EAMCET 2017 (24 Apr Shift 2)

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Solution:

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The correct answer is: $\frac{y-x^2}{y^2-x}$

No solution. Refer to answer key.

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