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Question: Answered & Verified by Expert
$\underline{X}$ and $\underline{Y}$ are the two covalent molecules in which the hybridisation of the central atoms is same, but shapes are different. $\underline{X}$ and $\underline{Y}$ are
ChemistryChemical Bonding and Molecular StructureAP EAMCETAP EAMCET 2018 (23 Apr Shift 1)
Options:
  • A $\mathrm{XeF}_4, \mathrm{NH}_3$
  • B $\mathrm{XeF}_2, \mathrm{PF}_5$
  • C $\mathrm{BF}_3, \mathrm{H}_2 \mathrm{O}$
  • D $\mathrm{CH}_4, \mathrm{BeCl}_2$
Solution:
1316 Upvotes Verified Answer
The correct answer is: $\mathrm{CH}_4, \mathrm{BeCl}_2$
The hybridisation in $\mathrm{XeF}_2$ and $\mathrm{PF}_5$ both is $s p^3 d$ thus they must have trigonal bi-pyramidal geometry. But, due to the presence of 3 lone pair and 2 bond pair shape of $\mathrm{XeF}_2$ get distorted and the molecule appears linear. But in case of $\mathrm{PCl}_5$ this is not so.

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