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Xenon hexafluoride on partial hydrolysis produces compounds ' $\mathrm{X}$ ' and ' $\mathrm{Y}$ '. Compounds ' $\mathrm{X}$ ', 'Y' and the oxidation state of $\mathrm{Xe}$ are respectively:
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$\mathrm{XeOF}_4(+6)$ and $\mathrm{XeO}_2 \mathrm{~F}_2(+6)$
$$
\text { } \mathrm{XeF}_6+\mathrm{H}_2 \mathrm{O} \frac{\text { partial }}{\text { hydrolysis }} \stackrel{+6}{\mathrm{XeOF}_4}+2 \mathrm{HF}
$$
\text { } \mathrm{XeF}_6+\mathrm{H}_2 \mathrm{O} \frac{\text { partial }}{\text { hydrolysis }} \stackrel{+6}{\mathrm{XeOF}_4}+2 \mathrm{HF}
$$
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